std::declare_no_pointers

 

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在标头 <memory> 定义
void declare_no_pointers( char *p, std::size_t n );		(C++11 起) (C++23 移除)

告诉垃圾收集器或泄漏检测器，指定的内存区域（从 p 所指向的字节开始的 n 个字节）不含可追踪指针。若区域的任何部分在分配的对象内，则同一对象中必须含有整个区域。

参数

p	-	指向范围起始的指针
n	-	范围中的字节数

返回值

（无）

异常

不抛出。

参阅

undeclare_no_pointers (C++11)(C++23 移除)

取消 std::declare_no_pointers 的效果 (函数)