How to find size of an object in Python?
In python, the usage of sys.getsizeof() can be done to find the storage size of a particular object that occupies some space in the memory. This function returns the size of the object in bytes. It takes at most two arguments i.e Object itself.
Note: Only the memory consumption directly attributed to the object is accounted for, not the memory consumption of objects it refers to.
Examples:
Input:
# Any Integer Value
sys.getsizeof(4)
Expected Output: 4 bytes (Size of integer is 4bytes)
Actual Output: 28 bytes
Here’s how we can interpret the actual output. Have a look at the table below:
Type of Object | Actual Size | Notes |
|---|---|---|
int | 28 | NA |
str | 49 | +1 per additional character (49+total length of characters) |
tuple | 40 (Empty Tuple) | +8 per additional item in a tuple ( 40 + 8*total length of items ) |
list | 56 (Empty List) | +8 per additional item in a list ( 56 + 8*total length of items ) |
set | 216 | 0-4 take the size of 216. 5-19 take size 728. 20th will take 2264 and so on… |
dict | 232 | 0-5 takes a size of 232. 6-10 size will be 360. 11th will take 640 and so on… |
func def | 136 | No attributes and default arguments |
Example:
Python3
import sys# Getting size using getsizeof() method and lately# printing the same.a= sys.getsizeof(12)print(a)b= sys.getsizeof('geeks')print(b)c= sys.getsizeof(('g','e','e','k','s'))print(c)d= sys.getsizeof(['g','e','e','k','s'])print(d)e= sys.getsizeof({1,2,3,4})print(e)f= sys.getsizeof({1:'a',2:'b',3:'c',4:'d'})print(f) |
Output:
